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A person exerts a force on a baseball that is 30 times the ball's weight. How fast is the pitcher accelerating the ball?

A. g
B. 2g
C. 3g
D. 30g

User Quan
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1 Answer

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Final answer:

The acceleration of the baseball when a force 30 times its weight is applied is 30g, according to Newton's second law of motion. Thus, the correct answer is D. 30g.

Step-by-step explanation:

If a person exerts a force on a baseball that is 30 times the ball's weight, to determine how fast the pitcher is accelerating the ball, we can use Newton's second law of motion.

The weight of the ball is the force due to gravity, which can be calculated as the mass of the ball (m) multiplied by the acceleration due to gravity (g). The total force (F) exerted on the ball is then 30 times the weight of the ball (30mg).

According to Newton's second law, F = ma, where a is the acceleration. If F is 30 times the weight of the ball (which is mg), we have:

30mg = ma

By dividing both sides of the equation by the mass of the ball, we find that the acceleration a is 30g.

Therefore, the correct answer is D. 30g.

To determine the acceleration of the baseball, we need to calculate the net force on the baseball using the formula Fnet = ma, where Fnet is the net force, m is the mass of the baseball, and a is the acceleration.

The weight of the baseball is given by W = mg, where W is the weight, m is the mass of the baseball, and g is the acceleration due to gravity. Since the force exerted on the baseball is 30 times its weight, we have F = 30mg.

Substituting this into the equation Fnet = ma, we get 30mg = ma. Cancelling out the mass, we can solve for the acceleration, a. Therefore, the correct option is D. 30g.

User Igor Soloydenko
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