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the altitude of hubble’s orbit is about 569 km above the surface of the earth. calculate the circumference of the orbit, the orbital velocity, and the period of the orbit

User Nilay Jha
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Final answer:

To find Hubble's orbit circumference, add its altitude to Earth's radius and use the orbital circumference formula, resulting in approximately 43,600 km.

Step-by-step explanation:

To calculate the circumference of Hubble's orbit, we use the formula = 2πr where 'r' is the sum of Earth's radius and Hubble's orbital altitude. The Earth's radius is approximately 6371 km, so the orbital radius 'r' for Hubble is 6371 km + 569 km = 6940 km. Therefore, the circumference is 2 * π * 6940 km = 43,600 km (approx).

To calculate the orbital velocity, we use the formula v = √(GM/r), where G is the gravitational constant (6.674×10⁻¹¹ m³/kg·s·s²), M is the mass of the Earth (5.972×10²´ kg), and 'r' is the orbital radius. Substituting the values, we get an approximate orbital velocity of 7.6 km/s.

The orbital period T can be found using T = 2πr / v. Using the circumference and the velocity we calculated, we get an orbital period of approximately 95.9 minutes.

User Redtopia
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