Final answer:
To find Hubble's orbit circumference, add its altitude to Earth's radius and use the orbital circumference formula, resulting in approximately 43,600 km.
Step-by-step explanation:
To calculate the circumference of Hubble's orbit, we use the formula = 2πr where 'r' is the sum of Earth's radius and Hubble's orbital altitude. The Earth's radius is approximately 6371 km, so the orbital radius 'r' for Hubble is 6371 km + 569 km = 6940 km. Therefore, the circumference is 2 * π * 6940 km = 43,600 km (approx).
To calculate the orbital velocity, we use the formula v = √(GM/r), where G is the gravitational constant (6.674×10⁻¹¹ m³/kg·s·s²), M is the mass of the Earth (5.972×10²´ kg), and 'r' is the orbital radius. Substituting the values, we get an approximate orbital velocity of 7.6 km/s.
The orbital period T can be found using T = 2πr / v. Using the circumference and the velocity we calculated, we get an orbital period of approximately 95.9 minutes.