Question

Is the reaction below endothermic or exothermic Hg(l) + 1/2O2(g) -> HgO(s) ∆H= -90.7 kJ

A) exothermic
B) endothermic

Answer 1

The reaction involving mercury and oxygen to form mercury(II) oxide is exothermic, as shown by its negative enthalpy change of -90.7 kJ.

Step-by-step explanation:

The reaction Hg(l) + 1/2O2(g) → HgO(s) with an enthalpy change (ΔH) of -90.7 kJ is an exothermic reaction. In an exothermic reaction, the energy is released to the surroundings, usually as heat, which is indicated by a negative ΔH value. This contrasts with an endothermic reaction, where energy is absorbed from the surroundings, which would be indicated by a positive enthalpy change.