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How much work does the water give out when heat is transferred to a 1.5-kg block of ice at -10°C, melting it to liquid at 10°C in a kitchen?

a. -45 kJ
b. 45 kJ
c. 90 kJ
d. -90 kJ

1 Answer

3 votes

Final answer:

The water gives out 563.7 kJ of work when heat is transferred to the block of ice.

Step-by-step explanation:

The amount of work done when heat is transferred to the block of ice can be calculated using the equation:

Work = mass of ice x specific heat capacity of ice x change in temperature

First, we need to calculate the heat required to melt the ice:
Q = mass of ice x latent heat of fusion
Q = 1.5 kg x 334 kJ/kg = 501 kJ

Next, we need to calculate the heat required to heat the liquid water:
Q = mass of liquid water x specific heat capacity of water x change in temperature
Q = 1.5 kg x 4.18 kJ/kg°C x (10°C - 0°C) = 62.7 kJ

Finally, we can calculate the total work done:
Work = 501 kJ + 62.7 kJ = 563.7 kJ

Therefore, the water gives out 563.7 kJ of work when heat is transferred to the block of ice.

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