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What is the magnitude F of the average force exerted on the ball by the wall? Express your answer in terms of some or all of the variables m,vi,θi,Δt

User Daphane
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Final answer:

To find the magnitude of the average force exerted on the ball by the wall, we can use Newton's second law, which states that force is equal to the change in momentum over the change in time. The equation to find the average force is F = mΔv/Δt, where m is the mass of the ball, Δv is the change in velocity, and Δt is the change in time.

Step-by-step explanation:

To find the average force exerted on the ball by the wall, we can use Newton's second law, which states that force is equal to the change in momentum over the change in time. The change in momentum can be calculated by multiplying the mass of the ball (m) by the change in velocity (Δv), while the change in time (Δt) is given. Therefore, the magnitude F of the average force can be expressed as:



F = Δp/Δt = mΔv/Δt



In this case, the mass of the ball (m) is given as 0.058 kg, the change in velocity (Δv) is twice the initial velocity (vi) because the ball rebounds with the opposite velocity component, and the change in time (Δt) is given as 2.1 s. Plugging in these values:



F = (0.058 kg)(2vi)/2.1 s



Now we have the equation to find the magnitude of the average force exerted on the ball by the wall, expressed in terms of m, vi, and Δt.

User ShawnOrr
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