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M&M plain candies have p = .8565 gm, and o - .0518 gm. The package label shows a weight of

396.9 gm, so 7 - .8535 gm. Every package has 465 m&m's.
Find the probability that one m&m weighs more than 8535 grams.
b. Find the probability that 465 m&m's have a mean weight greater than 8535 grams.

1 Answer

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Final answer:

a. The information provided is inconsistent, and the probability cannot be determined accurately without clarification on the weights of M&M candies.

b. Probability calculation for the mean weight of 465 M&M's requires additional information on the distribution of single M&M weights.

Step-by-step explanation:

There seems to be some inconsistency in the provided information, but I will try to address the issues and provide an approach to calculate the probabilities.

Let's clarify the information:

- It seems like there might be a typo with the values provided for the weights of M&M candies. You mentioned p = .8565 gm and o = .0518 gm, but then you say 7 - .8535 gm, which seems inconsistent.

Assuming you meant to write 7 - .8565 gm and o = .0518 gm, I will proceed with that assumption.

a. Probability that one M&M weighs more than 8.535 grams:

If the weight of one M&M is p = .8565 gm, and you want to find the probability that one M&M weighs more than 8.535 grams, it seems like there might be an issue with the values. Please confirm the correct values for clarity.

b. Probability that 465 M&M's have a mean weight greater than 8.535 grams:

To find the probability that the mean weight of 465 M&M's is greater than 8.535 grams, you need additional information about the distribution of weights or the mean weight of a single M&M. Without this information, it's challenging to calculate the probability accurately.

If you have the mean and standard deviation of the weights of a single M&M, you can use the Central Limit Theorem to approximate the distribution of the sample mean for a large sample size (465) and then find the probability.

User Potatoswatter
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