Question

R-134a flows through a diffuser. The inlet velocity is 112 m/s. It's pressure is 800kPa and the T=70C. If the mass flow rate has to be 1.42kg/s, what is the area of the diffuser inlet (cm2)? A.0.904 O B.4.43 oC. 0.000443 O D.0.507 O E. 0.000397 F.3.97

Answer 1

The area of the diffuser inlet is approximately 11.17 cm2.

Step-by-step explanation:

To find the area of the diffuser inlet, we can use the continuity equation, which states that mass flow rate is constant for an incompressible fluid in a steady flow. The equation is given by:

mass flow rate = density x velocity x area

Given that the mass flow rate is 1.42 kg/s and the velocity is 112 m/s, we can rearrange the equation to solve for the area:

area = mass flow rate / (density x velocity)

To convert from kg/s to cm2, we need to convert the units of area from m2 to cm2, which is done by multiplying the computed area by 10,000:

area = (mass flow rate / (density x velocity)) * 10,000

Substituting the values of mass flow rate, density, and velocity, we can calculate the area:

area = (1.42 / (1.14 x 112)) * 10,000 = 11.17 cm2

Therefore, the area of the diffuser inlet is approximately 11.17 cm2.