Question

Which map is correct? R 10 CM 3 CM awawala Rr Tt x rr tt Testcross Phenotype Counts RT 462 468 33 rT 37 antara 10 CM Rt Questions 9 - 10. According to the following results: Phenotype Offspring Phenotype АВС 351 ABC abc 354 abc авс Abc Abc Offspring super 48 47 96 а Вс 9. What gene is in the middle? 10. What is the final map of the three genes? mundillo 2. For the following recombination frequencies of 7 gene loci (a, b, c, d, e, f, and g). determine linkage groups, the order of the loci in each linkage group, and the distance between the loci of each group. Loci Loci a and b a and c a and d a and e a and f a and g Recombination Loci Recombination Loci Frequency Frequency 0.50 bandc0 .10 cand d 0.50 band d 0.50 cand e 0.12 band e 0.18 cand f 0.50 band f 0.50 cand g 0.50 band g 0.50 d and e 0.04 Recombination Frequency 0 .50d 0.28 0.50 0.50 e 0.50 and f d and g e and f and g fand g Recombination Frequency 0.50 0.08 0.50 0.50 0.50

Answer 1

The gene in the middle is gene 'c', with the final genetic map ordering genes b, c, and d based on recombination frequencies converted to centimorgans. Determining linkage groups and order requires identifying loci with recombination frequencies less than 0.50, with b-c-d being one such linked group.

Step-by-step explanation:

In genetic mapping, the gene in the middle can be determined by finding the gene that has recombination frequencies that are intermediate between the other two. When we look at the provided recombination frequencies, gene c is the one with intermediate recombination frequencies with genes b (0.10) and d (0.12). Hence, the gene c is in the middle. To create the final genetic map, one would place gene b at one end, gene d at the other end, and gene c in between, spaced according to the recombination frequencies which can be converted into centimorgans (CM).

For question 2, determining linkage groups requires identifying which loci exhibit recombination frequencies of less than 0.50, indicating linkage. The loci with recombination frequencies of 0.50 are assorting independently and not linked. From the frequencies provided, genes b and c (0.10), genes c and d (0.12), genes d and e (0.04), and genes d and g (0.28) show linkage.

The order within each linkage group can be determined by the recombination frequencies, with smaller frequencies suggesting closer proximity. Therefore, the order for some of the linked genes would be b-c-d, with distances between each gene corresponding to their recombination frequency: b to c is 10 CM and c to d is 12 CM. Additional data would be required to determine the exact order for all seven loci if they exhibit linkage beyond the examples provided.