Final answer:
In a normal distribution with a mean of 100 and a standard deviation of 15, the middle 50% of IQs fall between approximately 102 and 112.
Step-by-step explanation:
In a normal distribution with a mean of 100 and a standard deviation of 15, the middle 50% of IQs fall between the 25th and 75th percentiles.
To find these values, we use the z-score formula:
z = (x - mean) / standard deviation
For the lower bound:
z = (85 - 100) / 15 = -1
For the upper bound:
z = (115 - 100) / 15 = 1
Using a z-table, we find the corresponding percentiles for z = -1 and z = 1, which are approximately 0.1587 and 0.8413, respectively.
The middle 50% of IQs fall between the 16th percentile (0.1587) and the 84th percentile (0.8413).
Converting these percentiles back to IQ values:
Lower bound: IQ = (0.1587 * 15) + 100 = 102.38 ≈ 102
Upper bound: IQ = (0.8413 * 15) + 100 = 112.12 ≈ 112
Therefore, the middle 50% of IQs fall between approximately 102 and 112.