Question

An RMS potential difference of 1.98×10² V is measured across an AC circuit element where the RMS current is 3.50 A. What is the impedance of the circuit?

a) 56.57Ω
b) 70.86Ω
c) 100Ω
d) 150Ω

Answer 1

The impedance of the AC circuit with an RMS potential difference of 1.98×10² V and an RMS current of 3.50 A is calculated using Ohm's Law for AC circuits as 56.57Ω.

Step-by-step explanation:

To determine the impedance of an AC circuit when given the root-mean-square (RMS) potential difference and the RMS current, we can use Ohm's Law for AC circuits which states that the current (I) through a circuit is equal to the voltage (V) across the circuit divided by the impedance (Z), I = V/Z. This can also be written as Z = V/I.

In this case, we have a RMS potential difference of 1.98×10² V and an RMS current of 3.50 A. Using the formula for impedance, we get:

Z = V/I = (1.98×10² V) / (3.50 A) = 56.57Ω

Therefore, the impedance of the circuit is 56.57Ω, which corresponds to option (a).