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Use the chain rule to find dz/dt in terms of t when z=x²y²xy, x=sin(t), and y=eᵗ.

a. 2e²ᵗsin(t)+4e²ᵗcos(t)
b. 2e²ᵗsin(t)+2eᵗcos(t)
c. e²ᵗsin(t)+4e²ᵗcos(t)
d. e²ᵗsin(t)+2eᵗcos(t)

User Sieryuu
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1 Answer

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Final answer:

The correct answer is A. To find dz/dt in terms of t, we use the chain rule and substitute x = sin(t) and y = eᵗ into the partial derivatives of z with respect to x and y. The final expression for dz/dt is 2e²ᵗsin(t) + 4e²ᵗcos(t).

Step-by-step explanation:

To find dz/dt in terms of t using the chain rule, we start by finding the partial derivatives of z with respect to x and y.

The partial derivative of z with respect to x is 2xy²y + x²(2y) and the partial derivative of z with respect to y is x²(2xy).

Next, we substitute x = sin(t) and y = eᵗ into the partial derivatives and multiply by the corresponding derivatives of x and y with respect to t.

The derivative of x = sin(t) with respect to t is cos(t) and the derivative of y = eᵗ with respect to t is eᵗ.

Finally, we evaluate these expressions to find dz/dt in terms of t: 2e²ᵗsin(t) + 4e²ᵗcos(t).

User Tbolender
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