Final answer:
To find the distance between the two stones when the second one has reached a speed of 12.0 m/s, we can use the equation for distance travelled by an object under constant acceleration.
Step-by-step explanation:
To solve this problem, we can use the equation for distance travelled by an object under constant acceleration: d = v0t + 0.5at2.For the first stone, the initial velocity v0 is 0 m/s, and the acceleration a is the acceleration due to gravity, which is approximately 9.8 m/s2
For the second stone, the initial velocity v0 is also 0 m/s, but the time t is 1.30 s. The acceleration a is again approximately 9.8 m/s2. Substituting these values into the equation, we can find the distance travelled by each stone. The difference in distance travelled by the two stones is the distance between them when the second stone has reached a speed of 12.0 m/s.
To determine how far apart the stones are, we calculate the fall time for the second stone to reach 12.0 m/s using the equation v = gt, where v is the final velocity, g is the acceleration due to gravity (9.8 m/s2), and t is the time in seconds. Once the fall time for the second stone is found, we find the distances traveled by the first and second stones separately and then find the difference between them.