Final answer:
The acceleration of the pitcher's arm when releasing the baseball is calculated to be 355.56 m/s². The horizontal distance the baseball travels before hitting the ground cannot be determined without the height from which it is thrown.
Step-by-step explanation:
To answer part a) of the question, we first need to calculate the acceleration of the pitcher’s arm. Using the formula final velocity (v) = initial velocity (u) + acceleration (a) × time (t), and knowing the baseball starts from rest (u = 0), we have 32.0 m/s = 0 + a × 0.0900 s. Solving for a gives us an acceleration of 355.56 m/s².
For part b), since the velocity the pitcher releases the ball is horizontal, we can ignore the horizontal motion when finding the time it takes for the ball to hit the ground. Using the formula distance = 1/2 × gravity × time² for vertical motion and assuming gravity to be 9.81 m/s², we set the vertical distance to 0 (as the pitcher and the ground are at the same height) and solve for time.
However, since we are ignoring typos in the question, we lack the necessary details such as the height from which the ball is thrown, preventing us from calculating the horizontal distance the baseball travels.