Final answer:
The current flowing in the circuit is 30mA.
Step-by-step explanation:
To determine the current flowing in the circuit, we need to consider the turn-on voltage of the diode. The current flowing in the circuit is 30mA. When the turn-on voltage (Vf) is greater than the forward voltage drop across the diode (Vd), the diode conducts current.
In this case, since Vf = 2V and Vd = 0V, the diode is conducting. Therefore, the current flowing through the resistor can be calculated using Ohm's law.
Using Ohm's law, the current (I) can be calculated as: I = V/R
Substituting the given values for Vb = 3V and R = 100Ω, we get: I = 3V / 100Ω = 0.03A = 30mA