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If [Cl₂] at 298 K is -22.92 × 10⁻6 m/s, what is the rate of change in [Cl₂] in the following reaction?

a) 0
b) -22.92 × 10⁻6
c) 22.92 × 10⁻6
d) -45.84 × 10⁻6

User Mikelle
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1 Answer

6 votes

Final answer:

The rate of change in the concentration of Cl₂ is equal to its rate of disappearance, which is -22.92 × 10⁻⁶ m/s, given the stoichiometry of 1:1 for Cl₂ in the reaction.

Step-by-step explanation:

The student has asked about the rate of change in [Cl₂] in a chemical reaction given that the rate of disappearance of Cl₂ at 298 K is -22.92 × 10⁻⁶ m/s. Without the stoichiometry of the reaction, we cannot determine the exact rate of change in [Cl₂]. However, if we assume a stoichiometry of 1:1 for Cl₂, then the rate of change would be equal to the rate of disappearance. Therefore, the correct answer is (b) -22.92 × 10⁻⁶ m/s, which represents the rate of disappearance (decrease) of [Cl₂].

User Rob Fyffe
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