Question

A vertical force of is applied to the handle of the pipe wrench. Determine the moment that this force exerts along the axis ab (x axis) of the pipe assembly. Both the wrench and vector approach.

a) Need more information
b) Zero moment
c) 2 Nm
d) 4 Nm

Answer 1

OPTION A.The magnitude of the torque applied to the bolt is 23.1 N·m when a force of 165 N is exerted perpendicularly on a wrench at a distance of 0.140 m from the center of the bolt.

Step-by-step explanation:

The question relates to the concept of torque in Physics, which is a measure of the turning force on an object such as a wrench. To calculate torque (τ), the formula τ = rF sin θ is used, where r is the distance from the pivot point to the point where the force is applied, F is the magnitude of the force, and θ is the angle between the force vector and the lever arm. First, we must identify the force (F), the distance or lever arm (r), and the angle (θ).

For the case where a force of 165 N is applied perpendicularly at a distance of 0.140 m, the angle is 90 degrees (because the force is perpendicular), and thus the sin θ is 1. Therefore, the magnitude of the torque is τ = 0.140 m * 165 N * sin(90°) = 23.1 N·m.