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A star has a peak wavelength of 600 nm. Use Wien's law to compute the temperature of the star. Wien's law can be expressed as: T(K) = 3,000,000 nm /λmax.

a) 5,000 K
b) 4,000 K
c) 6,000 K
d) 3,000 K

User Fred Guth
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Final answer:

Using Wien's Law, the temperature of a star with a peak emission wavelength of 600 nm is calculated to be 5000 K, corresponding to answer option a) is correct.

Step-by-step explanation:

The subject of this question is Physics, and it is directed towards High School students. The student is asked to calculate the temperature of a star using Wien's Law, which relates the temperature of a blackbody to its peak emission wavelength. Given that the peak wavelength (λmax) of the star is 600 nm, we apply Wien's Law, which states that T(K) = 3,000,000 nm / λmax.

To find the temperature:

Insert the given peak wavelength into Wien's Law: T(K) = 3,000,000 nm / 600 nm.

Perform the division: T(K) = 3,000,000 nm / 600 nm = 5000 K.
Therefore, the temperature of this star is 5000 K, making option a) the correct answer.

According to Wien's law, the temperature of a star can be calculated using the formula: T(K) = 3,000,000 nm /λmax. Given that the peak wavelength of the star is 600 nm, we can substitute this value into the formula and solve for the temperature:

T(K) = 3,000,000 nm / 600 nm = 5000 K

Therefore, the temperature of the star is 5000 K.

User Bisw
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