Question

If I dilute 5 x 10³ ml of 6.0 M lithium acetate to a final volume of 10 x 10³ ml, what is the new concentration?

a) 3.0 M
b) 4.0 M
c) 5.0 M
d) 6.0 M

Answer 1

The new concentration of the lithium acetate solution after dilution is found to be 3.0 M. This is calculated using the formula M1V1 = M2V2 and by plugging in the given values for initial molarity, initial volume, and final volume.

Step-by-step explanation:

The question is related to the dilution of a lithium acetate solution and asks for the new concentration after the dilution process. To calculate the new concentration of a solution after dilution, we can use the formula M1V1 = M2V2, where M1 and V1 are the initial molarity and volume of the solution, respectively, and M2 and V2 constitute the molarity and volume of the diluted solution, respectively.

Initial concentration (M1) = 6.0 M
Initial volume (V1) = 5 x 10³ mL
Final volume (V2) = 10 x 10³ mL
We want to find the final concentration (M2).

Applying the formula:
6.0 M * 5 x 10³ mL = M2 * 10 x 10³ mL
Solving for M2, we get:
M2 = (6.0 M * 5 x 10³ mL) / (10 x 10³ mL)
M2 = 3.0 M

So the new concentration of the diluted lithium acetate solution is 3.0 M, which corresponds to option (a).