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In a remote region of space, far from any other objects, a small ball is in a 70-cm-radius circular orbit around a 7.0-kg bowling ball.

a) Calculate the gravitational force between the small ball and the bowling ball.
b) Determine the velocity of the small ball in its orbit.
c) Find the gravitational potential energy of the small ball.
d) All of the above

User Soheildb
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Final answer:

The correct answer is option d) All of the above.

Step-by-step explanation:

a) To calculate the gravitational force between the small ball and the bowling ball, we can use the equation F = G * (m1 * m2) / r^2, where F is the gravitational force, G is the gravitational constant (6.67 x 10^-11 N m^2 / kg^2), m1 and m2 are the masses of the small ball and the bowling ball respectively, and r is the distance between their centers. In this case, m1 = mass of the small ball = ? (not given), m2 = mass of the bowling ball = 7.0 kg, and r = radius of the circular orbit = 70 cm = 0.7 m. Substitute these values into the equation to find the gravitational force.

b) The velocity of the small ball in its orbit can be found using the equation v = √(G * (m2 / r)), where v is the velocity, G is the gravitational constant, m2 is the mass of the bowling ball, and r is the radius of the orbit. Substitute the given values into the equation to calculate the velocity.

c) The gravitational potential energy of the small ball can be calculated using the equation PE = -G * (m1 * m2) / r, where PE is the gravitational potential energy, G is the gravitational constant, m1 is the mass of the small ball, m2 is the mass of the bowling ball, and r is the distance between their centers.

User Aymen Alsaadi
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