Final answer:
To calculate the hangtime of an athlete's jump to 0.75 meters, kinematic equations are used to find the initial velocity needed to reach that height and then determine the time to ascend and descend, which combined gives the total hangtime.The correct option is c.
Step-by-step explanation:
The question asks to calculate the hangtime of an athlete who jumps to a height of 0.75 meters. To solve this we can use the kinematic equations. Assuming that the jump starts and ends at the same vertical position, we can ignore air resistance, and consider the acceleration due to gravity, which is approximately 9.81 m/s² downward.
Step-by-Step Solution:
Use the kinematic equation h = (v² - u²) / (2g), where h is the maximum height (0.75 m), v is the final velocity (0 m/s at the top of the jump), u is the initial velocity, and g is the acceleration due to gravity.
Rearrange the equation to solve for u: u = sqrt(2gh), which gives the initial velocity needed to reach the height of 0.75 m.
Calculate the time to reach the maximum height using the equation t = v / g, where t is the time and v is the initial velocity found in step 2.
Since the time to go up is the same as the time to come down, the total hangtime is twice the time calculated in step 3.
By applying this approach, the student can calculate the athlete's hangtime for a jump to 0.75 meters.The correct option is c.