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Compute δδ for the interval [3,8], where δ = 2−4.
a) -10
b) 16
c) -32
d) 5

User End User
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1 Answer

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Final answer:

δδ for the interval [3,8] where δ = 2−4 is equal to 16. OPTION B

Step-by-step explanation:

To compute δδ, first, it's necessary to understand that δ represents the change in the value within the interval [3, 8] when δ = 2−4.

The formula for δδ is given by the expression δδ = δ * (b - a), where a and b represent the endpoints of the interval. In this case, a = 3 and b = 8. Substituting these values into the formula, δδ = 2−4 * (8 - 3) = 2−4 * 5 = 16.

Therefore, δδ for the interval [3,8] where δ = 2−4 is 16. This indicates that the value changes by 16 units within the interval [3,8] when the value of δ is 2−4. Hence, the correct option is b) 16.

t.

User Danko Valkov
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