Final answer:
δδ for the interval [3,8] where δ = 2−4 is equal to 16. OPTION B
Step-by-step explanation:
To compute δδ, first, it's necessary to understand that δ represents the change in the value within the interval [3, 8] when δ = 2−4.
The formula for δδ is given by the expression δδ = δ * (b - a), where a and b represent the endpoints of the interval. In this case, a = 3 and b = 8. Substituting these values into the formula, δδ = 2−4 * (8 - 3) = 2−4 * 5 = 16.
Therefore, δδ for the interval [3,8] where δ = 2−4 is 16. This indicates that the value changes by 16 units within the interval [3,8] when the value of δ is 2−4. Hence, the correct option is b) 16.
t.