A metallic conductor has a resistivity of 18 x 10^-6 Ω*m. What is the resistance of a piece that is 30 m long and has a uniform cross sectional area of 3.0 x 10^-6 m^2?

Question

asked Jun 4, 2024 150k views

1 Answer

Furkan Yurdakul · Answer 1 · 2024-06-10T11:28:54+0000

The resistance of the piece of conductor is 180 Ω.

The resistance of a piece of metallic conductor can be calculated using the formula:

R = (ρ * L) / A

Where R is the resistance, ρ is the resistivity, L is the length of the conductor, and A is the cross-sectional area of the conductor.

Using the values given, we can plug them into the formula:

R = (18 x 10^-6 Ω*m * 30 m) / (3.0 x 10^-6 m^2)

Simplifying the expression, we find that the resistance of the piece of conductor is 180 Ω.