Question

Joyce shot a basketball to make the winning 3-pointer in the

championship game. When she shot the ball it was 4 feet from
the ground. She stood 12 feet from the base of the basketball
hoop and the ball reached a maximum height of 16 feet when she
shot it. If the basketball moves in a parabolic motion, write the
equation of the basketball in graphing form.
f(x) = -1(x-6)² + 16
ƒ(x) = −2(x+6)² + 16
f(x) = -1/3(x − 6)² +16
f(x) = -1/12(x - 12)² + 16

Answer 1

The equation of the basketball in graphing form is f(x) = -1(x-6)^2 + 16. This equation represents a parabolic motion with the vertex at (6, 16).

Step-by-step explanation:

The equation of the basketball in graphing form can be written as f(x) = -1(x-6)² + 16. This equation represents a parabolic motion, with the vertex at (6, 16) and the maximum height at 16 feet. The coefficient of the x squared term determines the direction and steepness of the parabola. In this case, the coefficient is -1, which means the parabola opens downwards.