Final answer:
In a series circuit, the total resistance is the sum of individual resistances, the current is calculated using the voltage of the battery and total resistance, and the voltage drop at each resistor is found by multiplying the current by the resistance. Power dissipation is calculated with the square of the current times resistance, and the total power is voltage times current.
Step-by-step explanation:
When analyzing circuits, such as the one depicted in a figure, several calculations are necessary to fully understand the behavior of the circuit. We use Ohm's law and Kirchhoff's circuit laws to determine the behavior of electrical components within a circuit.
For the given circuit with resistors in series, the total resistance (Rs) can be found by simply adding the resistance values of each resistor. If we have resistors R1 = 1.00 Ω, R2 = 6.00 Ω, and R3 = 13.0 Ω, the total resistance would be Rs = R1 + R2 + R3 = 1.00 Ω + 6.00 Ω + 13.0 Ω = 20.0 Ω.
The current through the circuit can be found using the voltage output of the battery and the total resistance. If we have a 12.0 V battery, then using Ohm's law (I = V / R), the current I is 12.0 V / 20.0 Ω = 0.60 A.
To find the voltage drop across each resistor, we would multiply the current by the resistance of each resistor (V = I * R). For example, the voltage drop across R1 is 0.60 A * 1.00 Ω = 0.60 V.
The power dissipated by each resistor can be calculated using the formula P = I2 * R. For R1, it would be P1 = (0.60 A)2 * 1.00 Ω = 0.36 W.
Finally, the total power supplied by the battery is calculated by multiplying the total current by the voltage of the battery (Ptotal = V * I). For a 12.0 V battery and 0.60 A current, the total power supplied is 12.0 V * 0.60 A = 7.2 W.