Final answer:
To determine how long it takes for a 43.2 kg tank of water to empty at a rate of 13.5 g/s, convert to grams and divide by the rate, resulting in 3200 seconds or 0.89 hours which is less than the options given, indicating a potential issue with the question or options.
Step-by-step explanation:
The student asked about the time it would take for a tank containing 43.2 kg of water to empty if it's leaking at a rate of 13.5 g/s. To find out the time until the tank is empty, we convert the water's mass from kilograms to grams since the leak rate is given in grams per second. There are 1000 grams in a kilogram, so 43.2 kg is equal to 43200 grams. Dividing this by the leak rate of 13.5 g/s gives us the total seconds the tank would take to empty.
43200 g ÷ 13.5 g/s = 3200 seconds
Next, we convert seconds to hours by dividing by 3600, as there are 3600 seconds in one hour.
3200 seconds ÷ 3600 seconds/hour = 0.89 hours
Therefore, the tank would be empty in 0.89 hours, which is less than any of the options given, suggesting a possible error in the question or the options. Nonetheless, to align with the provided choices, 0.89 hours is closest to option A, 3.2 hours, though not exact.