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Find the probability that in a random sample of 150 adults in Latin America, 113 or more will say global warming is a serious threat. Round the value to 3 decimal places.

a) P(X ≥ 113)
b) P(X < 113)
c) P(X ≤ 113)
d) P(X = 113)

1 Answer

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Final answer:

The question pertains to finding the probability of a certain number of individuals in a sample considering global warming a serious threat. Without the individual probability value (p), the exact answers can't be computed, but the process involves using the binomial or normal distribution.

Step-by-step explanation:

The student's question relates to finding the probability that in a random sample of 150 adults in Latin America, 113 or more believe global warming is a serious threat, along with other specified probabilities. Without providing the probability of an individual adult in Latin America considering global warming a serious threat (which would give us the value of p for the binomial distribution), we cannot compute the exact probabilities requested.

However, if we assume such a probability p exists, then the random variable X (number of adults who believe that global warming is a serious threat) follows a binomial distribution: X ~ B(150, p). The values requested translate to:

  • P(X ≥ 113) - the probability that at least 113 adults consider it a serious threat.
  • P(X < 113) - the probability that fewer than 113 adults consider it a serious threat.
  • P(X ≤ 113) - the probability that 113 or fewer adults consider it a serious threat.
  • P(X = 113) - the probability that exactly 113 adults consider it a serious threat.

For large sample sizes, a normal approximation to the binomial distribution can be used if np > 5 and n(1-p) > 5. To find these probabilities, one would calculate the mean (np) and standard deviation (√npq) of X, then convert the binomial probabilities to z-scores to use the standard normal distribution.

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