Question

The current in a 26 mH inductor is known to be -10 A for t ≤ 0 and (-10cos400t - 5sin400t)e^(-200t) for t ≥ 0. Assume the passive sign convention.

a. 10e^(-200t)
b. -10e^(-200t)
c. 5e^(-200t)
d. -5e^(-200t)

Answer 1

The voltage across the inductor can be calculated using the formula V = L * di/dt, where L is the inductance and di/dt is the rate of change of current. the correct option not mention.

Step-by-step explanation:

The voltage across the inductor can be calculated by multiplying the inductance (L) by the rate of change of current (di/dt). Since the inductor is in series with a resistor, the rate of change of current is given by Ohm's law: di/dt = V/R, where V is the voltage across the resistor.

Using the given information, the voltage across the inductor at t = 2.0 ms can be calculated by substituting the values into the equation: V = L * di/dt = (26 mH) * (-10 A) = -260 mV. Similarly, at t = 4.0 ms, V = (26 mH) * (-5 A) = -130 mV, and at t = 8.0 ms, V = (26 mH) * (0 A) = 0 V.

In this case, the inductance is given as 26 mH and the current is specified for different time periods. By substituting the values, the voltage across the inductor at t = 2.0 ms is -260 mV, at t = 4.0 ms is -130 mV, and at t = 8.0 ms is 0 V.

The correct option not mention.