Question

Calculate the average kinetic energy, in J/mol, for a mole of O₂ at -23.0°C. Assume ideal gas behavior.

a) 0 J/mol
b) Non-zero value
c) Negative value
d) Cannot be determined

Answer 1

The correct answer is option b) Non-zero value.

Step-by-step explanation:

To calculate the average kinetic energy of a mole of O2 gas at -23.0°C, we can use the formula for the average kinetic energy per mole of an ideal gas, which is:

KE = (3/2)RT

Where KE is the average kinetic energy in Joules, R is the ideal gas constant (8.314 J/(mol°K)), and T is the absolute temperature in Kelvin.

To convert -23.0°C to Kelvin, we add 273.15 to the Celsius temperature:

T = -23.0 + 273.15 = 250.15 K

Now plug in the values:

KE = (3/2) × 8.314 J/(mol°K) × 250.15 K

KE = 3,121.18 J/mol

Therefore, the average kinetic energy for a mole of O2 at -23.0°C is 3,121.18 J/mol, which is a non-zero value.