Question

Calculate the acceleration of a skier heading down a 10-degree slope, assuming the coefficient of friction for waxed wood on wet snow. μₖ = 0.1

a) Not applicable
b) 1.63 m/s²
c) 9.81 m/s²
d) 5.67 m/s²

Answer 1

The acceleration of the skier heading down a 10-degree slope is approximately 1.63 m/s².

Step-by-step explanation:

To calculate the acceleration of a skier heading down a 10-degree slope, we can use the equation:

Acceleration = g * sin(theta) - (mu_k * g * cos(theta))

Where g is the acceleration due to gravity, mu_k is the coefficient of friction, and theta is the angle of the slope.

Given that mu_k = 0.1 and theta = 10 degrees, we can substitute these values into the equation:

Acceleration = 9.81 m/s² * sin(10) - (0.1 * 9.81 m/s² * cos(10))

Simplifying this expression, we find that the acceleration is approximately 1.63 m/s².