Question

calculate the value of the electric field, in newtons per coulomb, of the wave at the position x = -3.5 m at the time t = 0.0065 μs.

Answer 1

use the given equation Ex = (10 N/C) sin (20x - 500t) to find the electric field. The value of the electric field at x = -3.5 m at t = 0.0065 μs is approximately -2.63 N/C.

Step-by-step explanation:

To calculate the value of the electric field at a specific position and time, we need to use the given equation Ex = (10 N/C) sin (20x - 500t). In this equation, x represents the position and t represents the time.

Plugging in the values x = -3.5 m and t = 0.0065 μs, we can calculate the electric field:

Ex = (10 N/C) sin (20(-3.5) - 500(0.0065))

Ex = (10 N/C) sin (-70 - 3.25)

Ex = (10 N/C) sin (-73.25)

Ex ≈ -2.63 N/C

Therefore, the value of the electric field at x = -3.5 m at t = 0.0065 μs is approximately -2.63 N/C.