Question

Fe(NH4)2(SO4)2•6H2O molar mass.

a) 216 g/mol
b) 392 g/mol
c) 550 g/mol
d) 728 g/mol

Answer 1

The molar mass of Fe(NH4)2(SO4)2•6H2O is 392 g/mol.

Step-by-step explanation:

The molar mass of Fe(NH4)2(SO4)2•6H2O can be calculated by adding up the atomic masses of all the elements in the compound. The molar mass of Fe is 55.85 g/mol, the molar mass of N is 14.01 g/mol, the molar mass of H is 1.01 g/mol, the molar mass of S is 32.07 g/mol, and the molar mass of O is 16.00 g/mol. Multiplying these masses by their respective subscripts in the compound and adding them together, we get:

Molar mass = (2 x (55.85 g/mol)) + (24 x (14.01 g/mol)) + (8 x (1.01 g/mol)) + (2 x (32.07 g/mol)) + (4 x (16.00 g/mol)) + (12 x (1.01 g/mol)) = 392 g/mol