Question

decomposition of ammonium nitrate procudes water and di nitrogen oxide. predict how many grams of water will be produced from decomposition of .555kg of ammonium nitrate

Answer 1

The decomposition of 0.555 kg of ammonium nitrate is predicted to produce approximately 249.9 grams of water, calculated using stoichiometry based on the balanced chemical reaction and molar masses.

Step-by-step explanation:

To predict how many grams of water will be produced from the decomposition of 0.555 kg of ammonium nitrate, we need to set up a stoichiometry problem based on the balanced chemical reaction:

NH4NO3(s) → N2O(g) + 2H2O(g)

First, we convert 0.555 kg of ammonium nitrate to grams (555 g) because stoichiometric calculations are often done in grams. According to the reaction, every 1 mole of ammonium nitrate produces 2 moles of water. The molar mass of ammonium nitrate (NH4NO3) is approximately 80.04 g/mol, and the molar mass of water (H2O) is approximately 18.02 g/mol. Using stoichiometry:

1. Calculate the moles of ammonium nitrate: 555 g / 80.04 g/mol = 6.935 moles of NH4NO3.
2. Since 2 moles of water are produced per mole of ammonium nitrate, we have 6.935 moles * 2 = 13.87 moles of water.
3. Finally, convert the moles of water to grams: 13.87 moles * 18.02 g/mol = 249.9 g of water.

In conclusion, the decomposition of 0.555 kg of ammonium nitrate will produce approximately 249.9 grams of water.