Question

Which of the following equations has 444 as a possible value of z?

a. 3z + 150 = 994
b. 5z - 2 = 222
c. 7z + 21 = 490
d. 4z × 111 = 444

Answer 1

The equation that has 444 as a possible value of z is option d. 4z × 111 = 444. To solve this equation, divide both sides of the equation by 111 to isolate z. Therefore, z = 4.

Step-by-step explanation:

The equation that has 444 as a possible value of z is option d. 4z × 111 = 444.

To solve this equation, divide both sides of the equation by 111 to isolate z. Therefore, z = 444 ÷ 111 = 4.

When we substitute z = 4 into the equation, we get 4 × 111 = 444, which confirms that 444 is a possible value of z.