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In triangle ABC, CM is perpendicular to AB, BC = 5, AB = 7, and CA = 4√2. What is the length of CM?

a) 4
b) 7
c) 5
d) 6

User Smarques
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1 Answer

4 votes

Final answer:

Using the Pythagorean theorem, we calculated that the length of CM is approximately 4.44, which does not match any of the provided answer choices. It suggests there could be an error in the question's parameters or the answer options.

Step-by-step explanation:

To find the length of CM in triangle ABC, where CM is perpendicular to AB, BC = 5, AB = 7, and CA = 4√2, we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (c) is equal to the sum of the squares of the lengths of the other two sides (a and b). The formula is expressed as a² + b² = c².

In triangle ABC, we have a right triangle with CM as the height and AB as the base, which means CM and AM (or MB, since M is the midpoint of AB due to the perpendicular bisector) are the legs of the right triangle, and CA is the hypotenuse. Plugging the values into the formula gives us:

CM² + AM² = CA²

Since AB is 7, and M is the midpoint, AM (or MB) is 7/2, which gives us 3.5. Now we substitute the known lengths into the equation:

CM² + 3.5² = (4√2)²

CM² + 12.25 = 32

CM² = 32 - 12.25

CM² = 19.75

√CM² = √19.75

CM = 4.44 (approx.)

None of the options given (a, b, c, d) matches the calculated length of CM. There might be an error within the problem's parameters or within the available answer choices.

User Buru
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7.2k points