Final answer:
To make 124 g of ammonia (NH₃), you would need 101.92 grams of nitrogen (N₂).
Step-by-step explanation:
To calculate the number of grams of nitrogen required to make 124 g of ammonia (NH₃), we can start by looking at the balanced chemical equation:
N₂ + 3H₂ → 2NH₃
The molar mass of nitrogen (N₂) is 28 g/mol, and from the equation we can see that 1 mole of N₂ is required to produce 2 moles of NH₃. So, we need to convert the grams of NH₃ to moles:
124 g NH₃ * (1 mol NH₃ / 17 g NH₃) = 7.29 mol NH₃
Since the mole ratio is 1:2 for N₂ to NH₃, we can calculate the moles of N₂ required:
7.29 mol NH₃ * (1 mol N₂ / 2 mol NH₃) = 3.64 mol N₂
Finally, we can convert the moles of N₂ to grams:
3.64 mol N₂ * (28 g N₂ / 1 mol N₂) = 101.92 g N₂