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The distance between streets is around 80 m and the distance

between avenues is around 260 m, as shown below.
Point X is at the centre of the junction of 15th Street and 9th Avenue.
Point Y is at the centre of the junction of 24th Street and 5th Avenue.
Using the information above,
a) calculate the straight-line distance between point X and point Y.
b) calculate the shortest distance along the roads to get from point X
to point Y.
Give your answers to the nearest metre.
18th Street
17th Street
16th Street
15th Street
9 Avenue
8th Avenue
80 m
7th Avenue
260 m
6th Avenue

1 Answer

7 votes

Final answer:

The straight-line distance between point X and point Y is approximately 1262 m, while the shortest distance along the roads is 1760 m.

Step-by-step explanation:

The student has asked how to calculate the straight-line distance between point X and point Y, and the shortest distance along the roads between these two points.

a) Straight-line distance calculation:

Point X is located at the junction of 15th Street and 9th Avenue, while point Y is at the junction of 24th Street and 5th Avenue. There are 9 streets between 15th and 24th Streets (24-15), and 4 avenues between 9th and 5th Avenues (9-5).

So, the horizontal distance is 9 streets × 80 m/street = 720 m, and the vertical distance is 4 avenues × 260 m/avenue = 1040 m.

The straight-line distance can be found using the Pythagorean theorem: √(720² + 1040²) ≈ √(518400 + 1081600) ≈ √1593600 ≈ 1262 m (to the nearest metre).

b) Shortest road distance:

To travel along the roads from point X to point Y, one would first traverse 9 streets and then 4 avenues (or vice versa) for the shortest path.

Therefore, the shortest road distance is the horizontal distance plus the vertical distance: 720 m + 1040 m = 1760 m.

User Olkoza
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