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Find the sum of the first 11 terms of the following geometric sequence.
{2, 4, 8, 16, 32,...}

Find the sum of the first 11 terms of the following geometric sequence. {2, 4, 8, 16, 32,...}-example-1

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Final answer:

To calculate the sum of the first 11 terms of the geometric sequence {2, 4, 8, ..., 2048}, the formula for the sum of a geometric series is used, yielding a result of 4094.

Step-by-step explanation:

Sum of the First 11 Terms of a Geometric Sequence

To find the sum of the first 11 terms of the geometric sequence {2, 4, 8, 16, 32, ...}, we use the formula for the sum of a geometric series which is Sn = a(1 - rn) / (1 - r), where Sn is the sum of the first n terms, a is the first term, r is the common ratio, and n is the number of terms.

For this sequence, a = 2 and the common ratio r = 2 since each term is twice the previous term. Plugging in these values and the number of terms, n = 11, we get:

S11 = 2(1 - 211) / (1 - 2)

Calculating the above expression:

S11 = 2(1 - 2048) / (-1)

Therefore, the sum of the first 11 terms is S11 = 4094.

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