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How much salt is needed to prepare 200 ml of a 5% (w/v) solution? The molecular weight of salt is 58.4 g/mole.

A) 5 g
B) 10 g
C) 15 g
D) 20 g

User Vesse
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1 Answer

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Final answer:

To prepare a 200 ml solution with a concentration of 5% w/v of salt, you need to use 10 grams of sodium chloride.

Step-by-step explanation:

To determine how much salt (sodium chloride, NaCl) is needed to prepare 200 ml of a 5% (w/v) solution, we start by understanding that 5% (w/v) means 5 grams of salt per 100 ml of solution. Since we want to prepare 200 ml, we need to calculate the mass of solute that corresponds to 200 ml of solution:

  • (5 g of NaCl is to 100 ml solution) as (x g of NaCl is to 200 ml solution).

By setting up a proportion, we find:

5 g / 100 ml = x g / 200 ml

Now we cross multiply and solve for x:

(5 g) * (200 ml) = x g * (100 ml)

1000 g*ml = x g * 100 ml

x = 1000 g*ml / 100 ml

x = 10 g

Therefore, to prepare 200 ml of a 5% (w/v) salt solution, you need 10 grams of sodium chloride.

User A Better Oliver
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