59.4k views
1 vote
A 55 g particle is moving to the left at 25 m/s . how much net work must be done on the particle to cause it to move to the right at 44 m/s ? A) 1.12 J

B) 3.85 J
C) 6.75 J
D) 9.25 J

User EEAH
by
6.7k points

1 Answer

4 votes

Final answer:

To calculate the net work done on the particle, you need to find the change in its kinetic energy. The initial kinetic energy is given by (1/2)mv^2 where m is the mass of the particle and v is its velocity.

Step-by-step explanation:

To calculate the net work done on the particle, we need to find the change in its kinetic energy. The initial kinetic energy is given by (1/2)mv^2 where m is the mass of the particle and v is its velocity. The final kinetic energy can be calculated using the same formula. The net work done on the particle is equal to the change in kinetic energy.

Given that the particle initially has a mass of 55 g and a velocity of 25 m/s to the left, and it is desired to move the particle to the right with a velocity of 44 m/s, we can calculate the change in kinetic energy as follows:

Initial kinetic energy: (1/2)(0.055 kg)(25 m/s)^2 = 21.875 J

Final kinetic energy: (1/2)(0.055 kg)(-44 m/s)^2 = 27.28 J

Net work done: Final kinetic energy - Initial kinetic energy = 27.28 J - 21.875 J = 5.405 J

Therefore, the net work that must be done on the particle to cause it to move to the right at 44 m/s is approximately 5.405 J.

The final kinetic energy can be calculated using the same formula. The net work done on the particle is equal to the change in kinetic energy.

User MrPickles
by
7.4k points