Final answer:
To solve this projectile motion problem, we can use equations for maximum height, initial velocity, time of flight, and angle of projection. By plugging in the given values for each part of the question and solving the equations, we can find the answers.
Step-by-step explanation:
In order to solve this problem, we can use the equations of motion for projectile motion. Let's break down the problem into parts:
To find the maximum height reached, we need to determine the time it takes for the projectile to reach its highest point. We can use the equation:
h = (v^2 * sin^2(theta)) / (2 * g)
Where h is the maximum height, v is the initial velocity, theta is the angle of projection, and g is the acceleration due to gravity. Plugging in the values given in the question, we get:
h = (25^2 * sin^2(theta)) / (2 * 9.8)
Calculating this value will give you the maximum height reached.
The initial velocity refers to the magnitude and direction of the velocity with which the projectile was launched. In this case, the initial velocity is 25 m/s, as stated in the question.
The time of flight refers to the total time it takes for the projectile to travel from its launch point to the point where it lands. It can be calculated using the equation:
t=(2*v*sin(theta))/g
Where t is the time of flight, v is the initial velocity, theta is the angle of projection, and g is the acceleration due to gravity. Plugging in the values given in the question, we can calculate the time of flight.
The angle of projection refers to the angle at which the projectile is launched with respect to the horizontal. To find the angle of projection, we can use the equation:
theta = arcsin((h*g)/(v^2))
Where theta is the angle of projection, h is the maximum height reached, g is the acceleration due to gravity, and v is the initial velocity. Plug in the values obtained from the previous parts of the question to find the angle of projection.