Question

A 1 kg object is located at a distance of 6.4 x106 m from the center of a larger object whose mass is 6.0 x 1024 kg. 5. What is the size of the force acting on the smaller object?

Answer 1

Using Newton's universal law of gravitation with the given masses and distance, we find that the gravitational force acting on the 1 kg object is approximately 9.8 N.

Step-by-step explanation:

To calculate the gravitational force acting on the smaller object, we can use Newton's universal law of gravitation, which states that the force (F) between two masses (m1 and m2) is proportional to the product of the two masses divided by the square of the distance (r) between them, multiplied by the gravitational constant (G). The formula is: F = G*(m1*m2)/r2.

In this case, we have a 1 kg object (m1 = 1 kg) and a larger object with a mass of 6.0 x 1024 kg (m2). The distance between the centers of the two objects is 6.4 x 106 m.

The gravitational constant (G) is 6.674 x 10-11 N·m2/kg2. Plugging these values into the formula, we get:

F = (6.674 x 10-11 N·m2/kg2) * (1 kg * 6.0 x 1024 kg) / (6.4 x 106 m)2

After performing the calculation, F ≈ 9.8 N (newtons).

Therefore, the gravitational force acting on the 1 kg object is approximately 9.8 N.