Final answer:
The torque produced by the 50 N perpendicular force is 20 Nm. (option c)
Step-by-step explanation:
The torque (τ) exerted by a force at the end of a wrench is determined by multiplying the force (F) with the length of the wrench (r).
In this case, with a perpendicular force of 50 N and a wrench length of 0.2 m, the torque can be calculated using the formula τ = r ⋅ F Substituting the values, τ=0.2m⋅50N, resulting in a torque of 20 Nm. This implies that for every Newton applied at the end of the wrench, there is a rotational effect of 0.2 meters from the pivot point, resulting in a torque of 20 Newton meters. The significance of the perpendicular force and the lever arm's length lies in their combined effect on the wrench's ability to rotate around the pivot. The longer the lever arm, the greater the torque for a given force.
Thus, the torque produced by a 50 N perpendicular force at the end of the 0.2 m-long wrench is accurately calculated as 20 Nm, aligning with option c.
The torque produced by a 50 N perpendicular force at the end of a 0.2 m-long wrench is 20 Nm, aligning with option c.