157k views
5 votes
Prove that a closed subset of a compact set is compact. What is the proof for this mathematical statement?

User Ian Bishop
by
8.3k points

1 Answer

5 votes

Final answer:

To prove that a closed subset of a compact set is compact, we need to show that every open cover of the closed subset has a finite subcover. This can be done by taking advantage of the properties of closed sets and compact sets.

Step-by-step explanation:

To prove that a closed subset of a compact set is compact, we need to show that every open cover of the closed subset has a finite subcover. Let's assume that we have a closed subset C of a compact set K. Now, let Oα be an open cover of C. Since C is closed, its complement, K - C, is open. And since K is compact, it has a finite subcover, let's say O1, O2, ..., On that covers K. Since O1, O2, ..., On and Oα are open covers of C, their union will be a finite subcover of C. Therefore, a closed subset of a compact set is compact.

User Helton Malambane
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.