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The titration of 25.00 mL of 0.2215 M HCl is required 28.84 mL: What additional information or calculation is needed for this titration?

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Final answer:

To complete the titration calculation, the missing piece of information is the concentration of the titrant, typically NaOH. Using the volume of HCl and its molarity, along with the balanced chemical equation, the molarity of NaOH can be determined through stoichiometry and titration concepts.

Step-by-step explanation:

To complete the titration calculation mentioned, we need to know the concentration (Molarity) of the titrant used, which is typically a base such as NaOH. The initial information gives us the volume and concentration of HCl. Once we have the concentration of the base, we apply the titration formula:

moles HCl = Molarity HCl × Volume HCl

We then use stoichiometry, based on the balanced chemical equation, to find the moles of base that reacted:

HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l)

Since the reaction is 1:1, the moles of HCl will equal the moles of NaOH. Using the moles of NaOH and its volume, we can find the molarity:

Molarity NaOH = moles NaOH / Volume NaOH

Titration, molarity, and stoichiometry are the key concepts applied here to find the missing concentration of the titrant.

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