Final answer:
A 2000 kg car is slowed down uniformly from 20.0 m/s to 5.00 m/s in 4.00 s. The car's acceleration during the slowing down is -3.75 m/s². The car traveled a distance of 60.0 m during the deceleration.
Step-by-step explanation:
A. To calculate the car's acceleration during the slowing down, we can use the equation:
acceleration = (final velocity - initial velocity) / time
Plugging in the values, we get:
acceleration = (5.00 m/s - 20.0 m/s) / 4.00 s = -3.75 m/s²
Therefore, the car's acceleration during the slowing down is -3.75 m/s².
B. To determine the distance traveled during the deceleration, we can use the equation:
distance = (initial velocity + final velocity) / 2 * time
Plugging in the values, we get:
distance = (20.0 m/s + 5.00 m/s) / 2 * 4.00 s = 60.0 m
Therefore, the car traveled a distance of 60.0 m during the deceleration.
C. The relationship between initial and final velocities is that the car's final velocity is smaller than the initial velocity. In this case, the car slowed down, so the final velocity is less than the initial velocity.
D. The factors affecting the car's deceleration are the initial velocity of the car, the final velocity, and the time taken to slow down. Additionally, external factors such as friction and drag can also impact deceleration.