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A golfer can hit a golf ball a horizontal distance of over 300 m on a good drive. What maximum height will a 301.5 m drive reach if it is launched at an angle of 25 degrees:

A. Apply projectile motion equations to calculate the maximum height.
B. Determine the launch velocity of the golf ball.
C. Analyze the impact of launch angle on the trajectory.
D. Discuss the factors influencing the golf ball's trajectory.

User Danyapd
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Final answer:

To calculate the maximum height reached by a 301.5 m drive launched at an angle of 25 degrees, you can use projectile motion equations and resolve the initial velocity into its components. The launch angle affects the range and height of the projectile, and factors influencing the trajectory include initial velocity, launch angle, air resistance, and acceleration due to gravity.

Step-by-step explanation:

To calculate the maximum height reached by a 301.5 m drive launched at an angle of 25 degrees, we can apply projectile motion equations. The maximum height can be calculated using the formula:

ymax = (v0^2 * sin^2(theta)) / (2 * g)

where v0 is the launch velocity, theta is the launch angle, and g is the acceleration due to gravity. We can determine the launch velocity of the golf ball by resolving the initial velocity into its horizontal and vertical components. The horizontal component of the velocity can be found using:

v0x = v0 * cos(theta)

The vertical component of the velocity can be found using:

v0y = v0 * sin(theta)

Next, we can analyze the impact of the launch angle on the trajectory. The launch angle affects the range and height of the projectile. A higher launch angle typically results in a higher maximum height but a shorter range. Lastly, the factors influencing the golf ball's trajectory include the initial velocity, launch angle, air resistance, and the acceleration due to gravity.

User DenMark
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