Question

Which of the following equations has 4 as a possible value of z?

a) z−5=−1
b) 3z+2=14
c) 2z=8
d) z² −16=0

Answer 1

All of them

A) 4-5 = -1
B) 3(4)+2 = 14
12+2=14
C) 2(4) = 8
D) 4^2 - 16 = 0
16 - 16 = 0

Answer 2

To find the equation with 4 as a value of z, we solve each equation. Option (a), (b), and (c) have 4 as a possible value of z.

Step-by-step explanation:

To find the equation that has 4 as a possible value of z, we need to check each option.

1. For option (a), z - 5 = -1, we can solve for z:
   
   z = -1 + 5
   z = 4
2. For option (b), 3z + 2 = 14, we can solve for z:
   
   3z = 14 - 2
   3z = 12
   z = 4
3. For option (c), 2z = 8, we can solve for z:
   
   z = 8 / 2
   z = 4
4. For option (d), z² - 16 = 0, we can solve for z by factoring:
   
   (z - 4)(z + 4) = 0
   z - 4 = 0 or z + 4 = 0
   z = 4 or z = -4

Therefore, options (a), (b), and (c) all have 4 as a possible value of z.