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Find the roots of the equation: f(x)=64x2+6=31

Find the roots of the equation: f(x)=64x2+6=31-example-1
User Heschoon
by
3.0k points

2 Answers

8 votes

Answer:

x = 5/8=0.625 and x = -5/8=โˆ’0.625

Explanation:

f(x)=64x^2+6=31

Subtract 6 from both sides.

64x^2+6=31

Subtract 6 from 31 to get 25.

64x^2=25

Divide both sides by 64.

x^2=25/64

Take the square root of both sides of the equation.

x=5/8=0.625

x=-5/8=โˆ’0.625

User Akeem
by
3.8k points
12 votes

Answer:

5/8, -5/8

Explanation:

64x^2 = 25

divide both sides by 64

x^2 = 25/64

take the square root of both sides, and the negative square roots

User Pearbear
by
3.6k points