Question

How far will it go, given that the coefficient of kinetic friction is 0.17 and the push imparts an initial speed of 3.6 m/s? Express your answer using two significant figures.

a. 12 m
b. 21 m
c. 28 m
d. 36 m

Answer 1

The object will not travel any distance because the value is negative.

Step-by-step explanation:

To calculate the distance the object will travel, we can use the formula:

d = (v^2 - u^2) / (2 * μ * g)

Where:

• d is the distance traveled
• v is the final speed
• u is the initial speed
• μ is the coefficient of kinetic friction
• g is the acceleration due to gravity

Substituting the given values:

d = ((0^2) - (3.6^2)) / (2 * 0.17 * 9.8) = -20.62m

Since distance cannot be negative, the answer is 0m.

Answer 2

The far an object will go the coefficient of kinetic friction is 0.17 and the push imparts an initial speed of 3.6 m/s is approximately 6 m. Therefore, there is no correct option.

Step-by-step explanation:

To determine how far an object will go given the coefficient of kinetic friction and an initial speed, we need to use the equation of motion. The equation is: d = (v² - u²) / (2a), where d is the distance, v is the final speed, u is the initial speed, and a is the acceleration.

In this case, the object is experiencing friction, which opposes its motion. The acceleration due to friction can be calculated using the equation a = μk * g, where μk is the coefficient of kinetic friction and g is the acceleration due to gravity.

Given that the coefficient of kinetic friction is 0.17 and the initial speed is 3.6 m/s, the final speed can be calculated by setting the acceleration due to friction equal to the initial speed. So, we have:

μk * g = u² / (2d).

d = u² / (2 * μk * g)

Plugging in the values, we have:

d = (3.62) / (2 * 0.17 * 9.8) = 6 m (rounded to two significant figures).

Thus, there is no correct option.