Final answer:
Utilizing the Bohr model, the energy of an electron in the n=8 orbital of a Be3+ ion (with Z=4) is calculated to be -0.547 x 10^-18 joules.
Step-by-step explanation:
The question asks to use the Bohr model to determine the energy of an electron in the n=8 stationary state orbital in a Be3+ ion, which has a nuclear charge Z=4. Bohr's model can be applied to any single-electron ion by modifying the energy level equation to include the nuclear charge. The energy of an electron in orbit n is given by:
En = - (Z2 * RH * (1 / n2))
Where RH is the Rydberg constant for hydrogen (2.178 x 10-18 joules). For the Be3+ ion (Z=4) at n=8:
E8 = - (42 * 2.178 x 10-18 J * (1 / 82))
E8 = - (16 * 2.178 x 10-18 J * (1 / 64))
E8 = - (16 / 64) * 2.178 x 10-18 J
E8 = -0.547 x 10-18 J
Therefore, the energy of an electron in the n=8 state of a Be3+ ion is -0.547 x 10-18 joules.